又是撿取問題..刺客爪

wkf

267    Fade
273    Mind Blast
276    Death Sentry
277    Blade Shield
278    Venom
279    Shadow Master

要撿以上6個技能其中3個的可以怎樣寫...
ABC ABD ABE ABF
BCD BCE BCF
CDE CDF
DEF

有沒有簡單點的方法呀?

yunzhongcb

sffss

wkf

([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillFade] >= 1 && [SkillMindBlast] >= 1 && [SkillDeathSentry] >= 1
([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillFade] >= 1 && [SkillMindBlast] >= 1 && [SkillBladeShield] >= 1
([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillFade] >= 1 && [SkillMindBlast] >= 1 && [SkillVenom] >= 1
([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillFade] >= 1 && [SkillMindBlast] >= 1 && [SkillShadowMaster] >= 1

([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillDeath Sentry] >= 1 && [SkillMindBlast] >= 1 && [SkillBladeShield] >= 1
([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillDeath Sentry] >= 1 && [SkillMindBlast] >= 1 && [SkillVenom] >= 1
([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillDeath Sentry] >= 1 && [SkillMindBlast] >= 1 && [SkillShadowMaster] >= 1

([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillDeath Sentry] >= 1 && [SkillBladeShield] >= 1 && [SkillVenom] >= 1
([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillDeath Sentry] >= 1 && [SkillBladeShield] >= 1 && [SkillShadowMaster] >= 1

([Name] == Suwayyah || [Name] == ScissorsSuwayyah) && [Quality] <= superior && [Flag] != ethereal # [SkillBladeShield] >= 1 && [SkillVenom] >= 1 && [SkillShadowMaster] >= 1



寫好了, 只是想問可不可以簡化?

白色曼陀螺

6个相加>=7

iamiori

A+B+C+D+E+F >= 7
同上

wkf

[quote=白色曼陀螺,137374]6个相加>=7[/quote] 一只爪只可以有三招, A+B+C>=3 , 也有機會是A=3呀...我不明白 6个相加>=7

wkf

[quote=iamiori,137415]A+B+C+D+E+F >= 7
同上[/quote] 明白了3+3+1=7 可是不會撿1+1+1的, 我用你這個方法好了,謝謝!!